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Can I use the spread operator to merge two objects while excluding certain properties from one of them?

Asked on Nov 28, 2025

Answer

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Yes, you can use the spread operator to merge two objects and exclude certain properties by using destructuring assignment. Here's how you can do it:

<!-- BEGIN COPY / PASTE -->
        const obj1 = { a: 1, b: 2, c: 3 };
        const obj2 = { d: 4, e: 5 };

        // Destructure and exclude property 'b'
        const { b, ...obj1WithoutB } = obj1;

        // Merge the objects
        const mergedObj = { ...obj1WithoutB, ...obj2 };

        console.log(mergedObj); // Output: { a: 1, c: 3, d: 4, e: 5 }
        <!-- END COPY / PASTE -->

Additional Comment:

The spread operator (...) is used to copy properties from one object to another.
Destructuring assignment with the syntax "{ b, ...obj1WithoutB }" removes the property "b" from "obj1".
The final merged object, "mergedObj", includes all properties from "obj1" except "b", and all properties from "obj2".
This approach is clean and leverages ES6+ features effectively.

✅ Answered with JavaScript best practices.

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