Why does my async function return a Promise instead of the actual data when using await inside it?

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Why does my async function return a Promise instead of the actual data when using await inside it?

Asked on Dec 30, 2025

Answer

When you define an async function in JavaScript, it always returns a Promise. The use of "await" inside the function pauses the execution until the Promise is resolved, but the function itself still returns a Promise.

// Example of an async function
        async function fetchData() {
            const response = await fetch('https://api.example.com/data');
            const data = await response.json();
            return data;
        }

        // Using the async function
        fetchData().then(data => console.log(data));

Additional Comment:

The "async" keyword ensures that the function returns a Promise.
"await" pauses the function execution until the Promise is resolved, allowing you to work with the resolved value directly.
To get the actual data outside the async function, use ".then()" or "await" when calling the function.
Always handle errors with "try...catch" inside async functions for better error management.

✅ Answered with JavaScript best practices.

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Why does my async function return a Promise instead of the actual data when using await inside it?

Asked on Dec 30, 2025

Answer

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